# Reinforcement Pad Calculation for Branch Connection

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A reinforcement pad or RF pad is used to strengthen the fabricated or welded pipe branch connection joints. Standard branch fittings such as Tee and Olets Fittings are generally used to take out the branch from the header or runner pipe, but these standard fittings are not easily available and economical for a large size range.

In such cases, we are required to make the fabricated branch connection (stub-in or stub-on). Fabricated branch connections are not as strong as the standard branch fittings, so to recover this strength gap between the standard branch fittings and fabricated branch joints, it is required to use the reinforcement pad or RF pad. But, it is not compulsory that all the fabricated branch connection joints are required reinforcement pad.

In this article, we will learn, how to decide whether the reinforcement pad is required or not for the size combination of the header and branch pipe? What should be the thickness and dimensions of the RF pad or reinforcement Pad?

## Fabricated Branch Connection Nomenclature

A pipe having a fabricated or welded branch connection is weakened by cutting out some area from the header pipe to fit the branch pipe on to it.

Unless the wall thickness of the pipe is sufficient to sustain the pressure, it is necessary to provide added reinforcement pad. The amount of reinforcement or strength required to sustain the pressure is determined in accordance with para. 304.3.3 or 304.3.4 of ASME B31.3. Let’s see the nomenclature as per para 304.3.3 below-

Where,

A1 = Area removed from the header or run pipe
A2 = Extrathickness available in the header pipe
A3 = Extrathickness available in the branch pipe
A4 = Area of RF Pad & area of welding

L4 = Height of the reinforcement zone
β = Angle between axes of the branch and header or run pipe

d1 = Effective length removed from the run or header pipe
d2 = Half-width of the reinforcement zone
Db = Outside diameter of branch pipe
Dh = Outside diameter of run or header pipe

Th = Tb = Thickness after deducting mill tolerance from nominal pipe thickness or ordering thickness of run and branch pipe respectively

th = tb = Calculated pipe thickness as per the equation of para. 304.1 of ASME B31.3 for run and branch respectively.

C = Corrosion allowance
Tr = Minimum thickness of reinforcement pad

## Formulas used for Reinforcement Pad Calculation

To decide, whether the reinforcement pad or RF pad is required or not, the following formulas are used-

## Inputs Required for RF Pad Calculation

Run pipe material- A672Gr.B
Branch pipe material- A106 Gr.B
Run pipe type- Welded
Branch pipe type- Seamless
Dh 20″ = 508 mm
Db 14″ = 355.6 mm
β- 90°

Design Pressure- 503 Psi
Design Temperature- 400°C
Mill tolerance for run or header pipe- ±0.3 mm
Mill tolerance for branch pipe- ±12.5% mm
Corrosion allowances for run pipe (C)- 3 mm
Corrosion allowances for branch pipe (C)- 3 mm

Follow the below steps to get the result:

### Step 1: Calculate the Run and Branch Pipe Thicknesses

I have already written an article on Pipe Thickness Calculation. Click here to see the calculation steps

After following the steps mentioned in above articles, we have got the following value

th = 11.83 mm
tb = 7.06 mm

Now, we can get Th & Tb from the above value
Th = 16-0.3 = 15.70 mm
Tb = 15.09×0.875 = 13.20 mm

### Step 2: Find d1

Put the required values in equation (2) of formulas section

d1  = [355.6 – 2(13.20 – 3)] / Sin 90° = 335.20 mm

### Step 3: Calculate A1

Put the required values in equation (1)

A1  = 11.83 × 335.20 (2 – Sin 90°) = 3965.41 mm2

### Step 4: Find d2

Put the required values in equation (4)

d2  = Max[335.20 ; {(13.20-3)+(15.70-3)+(335.20/2)}]
= Max[335.20 ; 190.50]
d2  = 335.20 mm

### Step 5: Now, Calculate A2

Put the required values in equation (3)

A2  = [(2×335.20)-335.20)(15.70-11.83-3)]= 291.62 mm2

### Step 6: Find L4

Put the required values in equation (6)

L4  = Min[{2.5(15.70-3)} ; {2.5(13.20-3)+0}] (Considering Tr = 0)
= Min[31.75 ; 25.5]
L4  = 25.50 mm

### Step 7: Now, Calculate A3

Put the required values in equation (5)

A3 = 2×25.5(13.20-7.06-3)/Sin90° = 160.14 mm2

### Step 8: Find tc

Put the required values in equation (8)

tc  = Min [0.7×15.09 ; 6]
= Min [10.56 ; 6]
tc = 6 mm

### Step 9: Now, Calculate A4

Put the required values in equation (7)

A4 = 2×62 = 72 mm2

### Step 10: Check if A1≥A2+A3+A4

Add A2+A3+A4 = 291.62+160.14+72 = 523.76 mm2 and we have A1 = 3965.41 mm2

Now, we can see A1>A2+A3+A4

Therefore, it is clear that we need to provide an RF pad to strengthen the joint.

#### Important Note:

If A1<A2+A3+A4 then RF Pad or Reinforcement Pad is not needed to provide

In most cases, RF Pad thickness is the same as the header or run pipe thickness, but we need to cross-check whether the reinforcement pad can be made from the run pipe.

So, Let’s consider RF Pad is taken from the header with the outer diameter (Dr ) = 2Db = 711.20 mm and thickness (Tr ) = Th = 15.70 mm

Note: RF Pad diameter is taken as two times the outer diameter of the branch pipe.

### Step 1: Calculate L4 again considering RF Pad is already provided

L4  = Min[{2.5(Th-C)} ; {2.5(Tb-C)+Tr}]
L4  = Min[{2.5(15.70-3)} ; {2.5(13.20-3)+15.70}] =  291.62 mm2
= Min[31.75 ; 41.12]
L4  = 31.75 mm

### Step 2: Now, Calculate A3 considering RF Pad

A3 = 2×L4 (Tb-tb-C)
= 2×31.75 (13.20-7.06-3)
A3= 199.39 mm2

### Step 3: Calculate A4 considering RF Pad

A4 = [{2×d1 – (Db / Sinβ)}(Th)+2tc2]
= [{2×335.20 – (355.6/sin90°)}(15.70)+(2×62)]
A4= 5014.36 mm2

### Step 4: Now Check if A1<A2+A3+A4

We have from the old calculation,
A1 = 3965.41 mm2
A2 = 291.62 mm2

We know from the latest calculation,
A3= 199.39 mm2
A4= 5014.36 mm2

Now, let’s check the condition below
IF A1<A2+A3+A4 = 3965.41<291.62+199.39+5014.36
3965.41< 5505.37

We can see from the above calculation A1<A2+A3+A4

The above result ensures that a reinforcement pad can be made from the header or run pipe for our case.

If still A1A2+A3+A4 then we need to use a higher thickness pipe for reinforcement pad or RF pad.

We need to continue the calculation with the increased thickness of the pipe until the condition “A1<A2+A3+A4” met.

I hope, now you can easily do the calculation for Reinforcement Pad. Do practice once or twice with other examples to clear all the doubts. Thanks for reading.

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